Questions: Answered: 16 / 18 Progress saved Done Question 17 0 / 1 pt 100 rightleftarrows 99 Details Graph f(x)=x^2+8x+15 below by first selecting the correct shape, clicking the vertex, then clicking an x-intercept. Clear All Draw: Find the zeros of the function from the graph.

Solution Steps

The x-coordinate of the vertex is given by x = -b/2a. In this case, a = 1 and b = 8, so x = -8/2(1) = -4.

Substitute x = -4 into the equation to find the y-coordinate of the vertex: f(-4) = (-4)^2 + 8(-4) + 15 f(-4) = 16 - 32 + 15 f(-4) = -1

So, the vertex is at (-4, -1).

To find the x-intercepts, set f(x) = 0 and solve for x:

x^2 + 8x + 15 = 0

This factors to (x+3)(x+5) = 0

Therefore, the x-intercepts are x = -3 and x = -5.

Select the parabola opening upwards. Click on the vertex (-4, -1). Click on either x-intercept (-3, 0) or (-5, 0).

Final Answer