Questions: Question 17 1 pts P6 60+ is said to be the strongest biological oxidizing agent. The strong oxidizing potential of P 680+ is essential for its function because it is the receptor for the most excited electron in either photosystem of photosynthesis transfers its electrons to reduce NADP+ to NADPH obtains electrons from the oxygen atom in a water molecule is the molecule that transfers electrons to plastoquinone (Pq) of the electron transfer system

Question 17 1 pts P6 60+ is said to be the strongest biological oxidizing agent. The strong oxidizing potential of P 680+ is essential for its function because it is the receptor for the most excited electron in either photosystem of photosynthesis transfers its electrons to reduce NADP+ to NADPH obtains electrons from the oxygen atom in a water molecule is the molecule that transfers electrons to plastoquinone (Pq) of the electron transfer system
Transcript text: Question 17 1 pts $\mathrm{P}_{6} 60^{+}$is said to be the strongest biological oxidizing agent. The strong oxidizing potential of $\mathrm{P} 680^{+}$is essential for its function because it $\qquad$ is the receptor for the most excited electron in either photosystem of photosynthesis transfers its electrons to reduce $\mathrm{NADP}^{+}$to NADPH obtains electrons from the oxygen atom in a witer molecule is the molecule that transfers electrons to plastoquinone $(\mathrm{Pq})$ of the electron transfer system Previous Next
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Solution

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The answer is the third one: obtains electrons from the oxygen atom in a water molecule.

Explanation for each option:

  1. Is the receptor for the most excited electron in either photosystem of photosynthesis: This is incorrect. P680+ is not the receptor for the most excited electron; rather, it is the oxidized form of P680 after it has lost an electron. P680 is the primary electron donor in Photosystem II.

  2. Transfers its electrons to reduce NADP+ to NADPH: This is incorrect. The reduction of NADP+ to NADPH occurs in Photosystem I, not Photosystem II where P680+ is involved.

  3. Obtains electrons from the oxygen atom in a water molecule: This is correct. P680+ is a very strong oxidizing agent, which allows it to extract electrons from water molecules, leading to the release of oxygen. This process is known as photolysis of water.

  4. Is the molecule that transfers electrons to plastoquinone (Pq) of the electron transfer system: This is incorrect. While P680 is involved in the initial stages of electron transfer in Photosystem II, it is not directly responsible for transferring electrons to plastoquinone. Instead, electrons are transferred from P680 to pheophytin and then to plastoquinone.

In summary, the strong oxidizing potential of P680+ is essential because it allows the molecule to obtain electrons from water, facilitating the splitting of water molecules and the release of oxygen.

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