Questions: What is the output of the following code snippet? ``` public static void main(String[] args) int s; double f=365.25; s = f / 10; System.out.println(s); ``` 36 36.525 37 No output because the code snippet generates compilation errors

What is the output of the following code snippet?

```
public static void main(String[] args)

int s;
double f=365.25;
s = f / 10;
System.out.println(s);

```
36
36.525
37
No output because the code snippet generates compilation errors

Transcript text: What is the output of the following code snippet? ``` public static void main(String[] args) { int s; double f=365.25; s = f / 10; System.out.println(s); } ``` 36 36.525 37 No output because the code snippet generates compilation errors

Solution

Solution Steps

Step 1: Analyze the Code Snippet

The given code snippet is:

public static void main(String[] args) {
    int s;
    double f = 365.25;
    s = (int) f;
    System.out.println(s);
}

Step 2: Understand Type Casting

The variable f is a double with a value of 365.25. The code casts f to an integer and assigns it to s. In Java, casting a double to an integer truncates the decimal part.

Step 3: Determine the Output

The value of f (365.25) is cast to an integer, resulting in 365. The System.out.println(s); statement will print the value of s, which is 365.