Questions: The text does not contain any content related to a specific question, only placeholders for equations that are not provided.

The text does not contain any content related to a specific question, only placeholders for equations that are not provided.
Transcript text: The text does not contain any content related to a specific question, only placeholders for equations that are not provided.
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Solution

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Solution Steps

Step 1: Identify the slope (m) and y-intercept (b) for the first equation
  • For the first graph (Equation 4), identify two points on the line. Let's use the points (-4, 4) and (0, -2).
  • Calculate the slope (m) using the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \).
Step 2: Calculate the slope (m) for the first equation
  • Using the points (-4, 4) and (0, -2): \[ m = \frac{-2 - 4}{0 - (-4)} = \frac{-6}{4} = -\frac{3}{2} \]
Step 3: Identify the y-intercept (b) for the first equation
  • The y-intercept (b) is the point where the line crosses the y-axis. From the graph, it is clear that the line crosses the y-axis at (0, -2). \[ b = -2 \]

Final Answer for Equation 4

\[ m = -\frac{3}{2}, \quad b = -2 \]

Step 1: Identify the slope (m) and y-intercept (b) for the second equation
  • For the second graph (Equation 7), identify two points on the line. Let's use the points (-4, 3) and (4, -3).
  • Calculate the slope (m) using the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \).
Step 2: Calculate the slope (m) for the second equation
  • Using the points (-4, 3) and (4, -3): \[ m = \frac{-3 - 3}{4 - (-4)} = \frac{-6}{8} = -\frac{3}{4} \]
Step 3: Identify the y-intercept (b) for the second equation
  • The y-intercept (b) is the point where the line crosses the y-axis. From the graph, it is clear that the line crosses the y-axis at (0, 0). \[ b = 0 \]
Final Answer for Equation 7

\[ m = -\frac{3}{4}, \quad b = 0 \]

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