Questions: Solve the following system of equations. x^2 + y^2 = 28 x^2 - y = 8

Solve the following system of equations. x^2 + y^2 = 28 x^2 - y = 8
Transcript text: Solve the following system of equations. \[ \left\{\begin{array}{l} x^{2}+y^{2}=28 \\ x^{2}-y=8 \end{array}\right. \]
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Solution

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Solution Steps

Step 1: Identify the System of Equations

The given system of equations is: \[ x^2 + y^2 = -28 \] \[ x^2 - y^2 = 8 \]

Step 2: Analyze the First Equation

The first equation is: \[ x^2 + y^2 = -28 \] Since the sum of two squares (both non-negative) cannot be negative, this equation has no real solutions.

Step 3: Conclude No Real Solutions

Since the first equation has no real solutions, the system of equations has no real solutions.

Final Answer

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