Questions: Suppose that f(x) is continuous on (-∞, ∞). Sketch the graph of f such that f(-2)=4, f(0)=0, f(2)=-4 f'(−2)=0, f'(0)=0, f'(2)=0 f'(x)>0 on (-∞,-2) and (2, ∞)

Suppose that f(x) is continuous on (-∞, ∞). Sketch the graph of f such that
f(-2)=4, f(0)=0, f(2)=-4
f'(−2)=0, f'(0)=0, f'(2)=0
f'(x)>0 on (-∞,-2) and (2, ∞)
Transcript text: Suppose that $f(x)$ is continuous on $(-\infty, \infty)$. Sketch the graph of $f$ such that \[ \begin{array}{l} f(-2)=4, f(0)=0, f(2)=-4 \\ f^{\prime}(-2)=0, f^{\prime}(0)=0, f^{\prime}(2)=0 \end{array} \] \[ f^{\prime}(x)>0 \text { on }(-\infty,-2) \text { and }(2, \infty) \]
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the given points and their derivatives

The function \( f(x) \) is continuous and has the following points:

  • \( f(-2) = 4 \)
  • \( f(0) = 0 \)
  • \( f(2) = -4 \)

The derivatives at these points are:

  • \( f^{\prime}(-2) = 0 \)
  • \( f^{\prime}(0) = 0 \)
  • \( f^{\prime}(2) = 0 \)
Step 2: Determine the behavior of the function

The derivative \( f^{\prime}(x) \) is positive on the intervals:

  • \( (-\infty, -2) \)
  • \( (2, \infty) \)

This indicates that the function is increasing on these intervals.

Step 3: Analyze the critical points

The points where the derivative is zero, \( x = -2, 0, 2 \), are critical points. Since the derivative changes sign around these points, they are likely local maxima or minima.

Final Answer

The function \( f(x) \) has local maxima or minima at \( x = -2, 0, 2 \) and is increasing on \( (-\infty, -2) \) and \( (2, \infty) \).

{"axisType": 3, "coordSystem": {"xmin": -3, "xmax": 3, "ymin": -5, "ymax": 5}, "commands": ["f(-2) = 4", "f(0) = 0", "f(2) = -4"], "latex_expressions": ["$f(-2) = 4$", "$f(0) = 0$", "$f(2) = -4$"]}

Was this solution helpful?
failed
Unhelpful
failed
Helpful