Questions: Write a polynomial f(x) that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients, and with zeros 8-6i and 0 (multiplicity 3).
Transcript text: Write a polynomial $f(x)$ that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients, and with zeros $8-6 i$ and 0 (multiplicity 3 ).
Solution
Solution Steps
Step 1: Identify the Zeros
The polynomial \( f(x) \) is required to have the following zeros:
\( 0 \) with multiplicity \( 3 \)
\( 8 - 6i \) (and its conjugate \( 8 + 6i \) since the coefficients must be real)
Step 2: Construct the Polynomial
Using the identified zeros, we can express the polynomial as:
\[
f(x) = (x - 0)^3 \cdot (x - (8 - 6i)) \cdot (x - (8 + 6i))
\]
This simplifies to:
\[
f(x) = x^3 \cdot (x - (8 - 6i)) \cdot (x - (8 + 6i))
\]
Step 3: Expand the Polynomial
Upon expanding the polynomial, we obtain:
\[
f(x) = x^5 - 16x^4 + 100x^3
\]
Step 4: Factor the Polynomial
The polynomial can be factored as follows:
\[
f(x) = x^3 \left( x^2 - 16x + 100 \right)
\]
Final Answer
The polynomial \( f(x) \) that satisfies the given conditions is:
\[
\boxed{f(x) = x^3 \left( x^2 - 16x + 100 \right)}
\]