Questions: Systems of Linear Equations
Graphing a linear inequality in the plane: Slope-Intercept form
Graph the inequality:
y ≤ (1/3)x + 2
Transcript text: Systems of Linear Equations
Graphing a linear inequality in the plane: Slope-Intercept form
Graph the inequality:
$y \leq \frac{1}{3}x + 2$
[Graph coordinate plane with tools for drawing]
Explanation Check
Solution
Solution Steps
Step 1: Find the y-intercept
The y-intercept is the constant term in the inequality, which is 2. This means the line crosses the y-axis at the point (0, 2).
Step 2: Find the slope
The slope is the coefficient of x, which is -1/3. This means for every 3 units we move to the right along the x-axis, we move 1 unit down along the y-axis.
Step 3: Determine the type of line
Since the inequality is 'less than or equal to', ≤, we draw a solid line to indicate that points on the line are included in the solution set.
Step 4: Determine the shaded region
Since the inequality is y ≤ (-1/3)x + 2, we shade the region below the line. This represents all the points (x,y) that satisfy the inequality.
Final Answer:
The graph should be a solid line passing through (0, 2) with a slope of -1/3, and the region below the line should be shaded.