Questions: Solve the equation for (x). [ 6 x-1+3=17 ] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is (square) . (Simplify your answer. Type an exact answer, using radicals as needed. Use a comma to separate B. The solution set is (varnothing).

Solve the equation for (x).
[
6 x-1+3=17
]

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is (square) .
(Simplify your answer. Type an exact answer, using radicals as needed. Use a comma to separate
B. The solution set is (varnothing).
Transcript text: Solve the equation for $x$. \[ |6 x-1|+3=17 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is $\square$ \}. (Simplify your answer. Type an exact answer, using radicals as needed. Use a comma to separ B. The solution set is $\varnothing$.
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Solution

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Solution Steps

To solve the equation \(|6x - 1| + 3 = 17\), we first isolate the absolute value expression and then consider the two possible cases for the expression inside the absolute value.

  1. Isolate the absolute value: \(|6x - 1| = 14\).
  2. Consider the two cases:
    • Case 1: \(6x - 1 = 14\)
    • Case 2: \(6x - 1 = -14\)
  3. Solve each case for \(x\).
Step 1: Isolate the Absolute Value Expression

Given the equation: \[ |6x - 1| + 3 = 17 \] First, isolate the absolute value expression by subtracting 3 from both sides: \[ |6x - 1| = 14 \]

Step 2: Consider the Two Cases for the Absolute Value

The absolute value equation \(|6x - 1| = 14\) can be split into two cases:

  1. \(6x - 1 = 14\)
  2. \(6x - 1 = -14\)
Step 3: Solve Each Case for \(x\)
Case 1: \(6x - 1 = 14\)

\[ 6x - 1 = 14 \] Add 1 to both sides: \[ 6x = 15 \] Divide by 6: \[ x = \frac{15}{6} = \frac{5}{2} \]

Case 2: \(6x - 1 = -14\)

\[ 6x - 1 = -14 \] Add 1 to both sides: \[ 6x = -13 \] Divide by 6: \[ x = \frac{-13}{6} \]

Final Answer

\(\boxed{x = \frac{5}{2}, \frac{-13}{6}}\)

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