Questions: 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g) NO=

Transcript text: 2 C_{2} H_{2}(g)+5 O_{2}(g) \xrightarrow{\Delta} 4 CO_{2}(g)+2 H_{2} O(g) N_{O}=

Solution

Solution Steps

Step 1: Identify the Reactants and Products

The given chemical equation is:

\[ 2 \mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{~g})+5 \mathrm{O}_{2}(\mathrm{~g}) \xrightarrow{\Delta} 4 \mathrm{CO}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{~g}) \]

The reactants are \(2 \mathrm{C}_{2} \mathrm{H}_{2}\) and \(5 \mathrm{O}_{2}\), and the products are \(4 \mathrm{CO}_{2}\) and \(2 \mathrm{H}_{2} \mathrm{O}\).

Step 2: Count Oxygen Atoms in Reactants

In the reactants, we have:

\(5 \mathrm{O}_{2}\): Each \(\mathrm{O}_{2}\) molecule contains 2 oxygen atoms. Therefore, the total number of oxygen atoms in the reactants is: \[ 5 \times 2 = 10 \]

Step 3: Count Oxygen Atoms in Products

In the products, we have:

\(4 \mathrm{CO}_{2}\): Each \(\mathrm{CO}_{2}\) molecule contains 2 oxygen atoms. Therefore, the total number of oxygen atoms from \(\mathrm{CO}_{2}\) is: \[ 4 \times 2 = 8 \]
\(2 \mathrm{H}_{2} \mathrm{O}\): Each \(\mathrm{H}_{2} \mathrm{O}\) molecule contains 1 oxygen atom. Therefore, the total number of oxygen atoms from \(\mathrm{H}_{2} \mathrm{O}\) is: \[ 2 \times 1 = 2 \]

Adding these together gives the total number of oxygen atoms in the products: \[ 8 + 2 = 10 \]