Questions: Sketch a graph of y=-x^2-1

Sketch a graph of y=-x^2-1
Transcript text: Sketch a graph of $y=-x^{2}-1$
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Solution

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Solution Steps

Step 1: Identify the Equation and its Components

The given equation is \( y = -x^2 - 1 \). This is a quadratic equation in the form \( y = ax^2 + bx + c \) where \( a = -1 \), \( b = 0 \), and \( c = -1 \).

Step 2: Determine the Vertex

For the equation \( y = -x^2 - 1 \), the vertex form is \( y = a(x-h)^2 + k \). Here, \( h = 0 \) and \( k = -1 \), so the vertex is at \( (0, -1) \).

Step 3: Plot the Vertex

Plot the vertex \( (0, -1) \) on the graph.

Step 4: Determine the Direction of the Parabola

Since \( a = -1 \) (which is negative), the parabola opens downwards.

Step 5: Calculate Additional Points

Choose values for \( x \) to find corresponding \( y \) values:

  • For \( x = 1 \), \( y = -(1)^2 - 1 = -1 - 1 = -2 \)
  • For \( x = -1 \), \( y = -(-1)^2 - 1 = -1 - 1 = -2 \)
  • For \( x = 2 \), \( y = -(2)^2 - 1 = -4 - 1 = -5 \)
  • For \( x = -2 \), \( y = -(-2)^2 - 1 = -4 - 1 = -5 \)
Step 6: Plot Additional Points

Plot the points \( (1, -2) \), \( (-1, -2) \), \( (2, -5) \), and \( (-2, -5) \) on the graph.

Step 7: Draw the Parabola

Connect the points with a smooth curve to form the parabola.

Final Answer

The graph of \( y = -x^2 - 1 \) is a downward-opening parabola with its vertex at \( (0, -1) \). The additional points \( (1, -2) \), \( (-1, -2) \), \( (2, -5) \), and \( (-2, -5) \) help in shaping the curve.

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