Questions: Part F chromium(III) sulfate Express your answer in atomic mass units to one decimal place. Formula weight = amu Submit

Part F chromium(III) sulfate Express your answer in atomic mass units to one decimal place. Formula weight = amu Submit
Transcript text: Part F chromium(III) sulfate Express your answer in atomic mass units to one decimal place. View Available Hint(s) Formula weight $=$ $\square$ amu Submit
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Solution

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Solution Steps

Step 1: Determine the Chemical Formula

Chromium(III) sulfate is a chemical compound with the formula \(\text{Cr}_2(\text{SO}_4)_3\). This indicates that each formula unit contains 2 chromium (Cr) atoms, 3 sulfur (S) atoms, and 12 oxygen (O) atoms.

Step 2: Find Atomic Masses

The atomic masses of the elements involved are approximately:

  • Chromium (Cr): 51.9961 amu
  • Sulfur (S): 32.06 amu
  • Oxygen (O): 15.999 amu
Step 3: Calculate the Formula Weight

To find the formula weight of \(\text{Cr}_2(\text{SO}_4)_3\), we calculate the total mass contributed by each type of atom:

  • Mass of chromium: \(2 \times 51.9961 = 103.9922\) amu
  • Mass of sulfur: \(3 \times 32.06 = 96.18\) amu
  • Mass of oxygen: \(12 \times 15.999 = 191.988\) amu

Add these values together to find the total formula weight:

\[ 103.9922 + 96.18 + 191.988 = 392.1602 \text{ amu} \]

Step 4: Round to One Decimal Place

Round the total formula weight to one decimal place:

\[ 392.1602 \approx 392.2 \text{ amu} \]

Final Answer

The formula weight of chromium(III) sulfate is \(\boxed{392.2 \text{ amu}}\).

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