Questions: Which image represents the ionic compound strontium fluoride, SrF2?

Transcript text: Which image represents the ionic compound strontium fluoride, $\mathrm{SrF}_{2}$ ?

Solution

Solution Steps

Step 1: Understanding the Composition of Strontium Fluoride

Strontium fluoride, $\mathrm{SrF}_{2}$, is an ionic compound composed of strontium ions ($\mathrm{Sr}^{2+}$) and fluoride ions ($\mathrm{F}^{-}$). In this compound, each strontium ion is paired with two fluoride ions to balance the charges, as strontium has a +2 charge and each fluoride has a -1 charge.

Step 2: Identifying the Ionic Structure

In an ionic compound like $\mathrm{SrF}_{2}$, the structure is typically a crystal lattice where the cations and anions are arranged in a repeating pattern. The strontium ions ($\mathrm{Sr}^{2+}$) will be larger than the fluoride ions ($\mathrm{F}^{-}$) due to their lower charge density and larger ionic radius.

Step 3: Visualizing the Ionic Arrangement

In a visual representation of $\mathrm{SrF}_{2}$, you would expect to see a repeating pattern where each $\mathrm{Sr}^{2+}$ ion is surrounded by fluoride ions. The ratio of strontium ions to fluoride ions should be 1:2, reflecting the chemical formula.

Final Answer

The image representing the ionic compound strontium fluoride, $\mathrm{SrF}_{2}$, should show a crystal lattice with $\mathrm{Sr}^{2+}$ ions surrounded by twice as many $\mathrm{F}^{-}$ ions, maintaining a 1:2 ratio. The $\mathrm{Sr}^{2+}$ ions will be larger than the $\mathrm{F}^{-}$ ions.

$\boxed{\text{Image showing a 1:2 ratio of Sr to F ions in a crystal lattice.}}$

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