Questions: After a 100-lb. person steps on a bathroom scale and the reading is steady, the spring inside the scale is compressed with a force of (A) 100 lbs . (B) 50 lbs . (C) 200 lbs (D) 110 lbs .

After a 100-lb. person steps on a bathroom scale and the reading is steady, the spring inside the scale is compressed with a force of (A) 100 lbs . (B) 50 lbs . (C) 200 lbs (D) 110 lbs .
Transcript text: After a $100-\mathrm{lb}$. person steps on a bathroom scale and the reading is steady, the spring inside the scale is compressed with a force of $\qquad$ (A) 100 lbs . (B) 50 lbs . (C) 200 lbs (D) 110 lbs .
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Solution

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Solution Steps

Step 1: Understand the Problem
  • A person weighing 100 lbs steps on a bathroom scale.
  • The scale reading is steady, indicating equilibrium.
Step 2: Identify the Forces
  • The weight of the person (\( W \)) is 100 lbs.
  • The spring inside the scale exerts an upward force equal to the weight of the person to maintain equilibrium.
Step 3: Apply Newton's Third Law
  • According to Newton's Third Law, the force exerted by the spring must equal the weight of the person.
  • Therefore, the spring force is 100 lbs.
Step 4: Select the Correct Answer
  • The correct answer is (A) 100 lbs.

Final Answer

The correct answer is A.

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