Questions: A student sets up and solves the following equation to solve a problem in solution stoichiometry. Fill in the missing part of the student's equation. (0.36 (1 mL / 10^-3 L)(1.26 g / mL)) / (65.37 g / mol) = 6.9 mol

Solution Steps

The given equation is a stoichiometry problem where the student is trying to find the missing part, denoted by a square (□), in the equation:

\[ \frac{\left(0.36 \square\left(\frac{1 \mathrm{~mL}}{10^{-3} \mathrm{~L}}\right)\left(1.26 \frac{\mathrm{~g}}{\mathrm{~mL}}\right)\right)}{\left(65.37 \frac{\mathrm{~g}}{\mathrm{~mol}}\right)}=6.9 \mathrm{~mol} \]

To find the missing part, we need to rearrange the equation to solve for the square (□):

\[ 0.36 \square \left(\frac{1 \mathrm{~mL}}{10^{-3} \mathrm{~L}}\right)\left(1.26 \frac{\mathrm{~g}}{\mathrm{~mL}}\right) = 6.9 \mathrm{~mol} \times 65.37 \frac{\mathrm{~g}}{\mathrm{~mol}} \]

First, calculate the right side of the equation:

\[ 6.9 \times 65.37 = 450.053 \mathrm{~g} \]

Now, solve for the missing part (□):

\[ 0.36 \square \times 1.26 = 450.053 \]

\[ 0.4536 \square = 450.053 \]

\[ \square = \frac{450.053}{0.4536} = 992.1 \]

Final Answer