Questions: Find the mass of the thin bar with the given density function. ρ(x)=1+sin x ; for 0 ≤ x ≤ π/3 Set up the integral that gives the mass of the thin bar.

Find the mass of the thin bar with the given density function.
ρ(x)=1+sin x ; for 0 ≤ x ≤ π/3

Set up the integral that gives the mass of the thin bar.
Transcript text: Find the mass of the thin bar with the given density function. \[ \rho(x)=1+\sin x ; \text { for } 0 \leq x \leq \frac{\pi}{3} \] Set up the integral that gives the mass of the thin bar.
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Solution

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Solution Steps

To find the mass of the thin bar with the given density function, we need to integrate the density function over the given interval. The mass \( M \) of the bar can be found by evaluating the integral of the density function \(\rho(x)\) from \(0\) to \(\frac{\pi}{3}\).

Step 1: Define the Density Function and Limits

The density function of the thin bar is given by \(\rho(x) = 1 + \sin x\). We need to find the mass of the bar over the interval \(0 \leq x \leq \frac{\pi}{3}\).

Step 2: Set Up the Integral

To find the mass \(M\) of the bar, we set up the integral of the density function over the given interval: \[ M = \int_{0}^{\frac{\pi}{3}} (1 + \sin x) \, dx \]

Step 3: Evaluate the Integral

Evaluate the integral: \[ M = \left[ x - \cos x \right]_{0}^{\frac{\pi}{3}} \]

Step 4: Calculate the Definite Integral

Substitute the limits of integration: \[ M = \left( \frac{\pi}{3} - \cos\left(\frac{\pi}{3}\right) \right) - \left( 0 - \cos(0) \right) \] \[ M = \left( \frac{\pi}{3} - \frac{1}{2} \right) - (-1) \] \[ M = \frac{\pi}{3} - \frac{1}{2} + 1 \] \[ M = \frac{\pi}{3} + \frac{1}{2} \]

Final Answer

\(\boxed{M = \frac{\pi}{3} + \frac{1}{2}}\)

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