17≤x2+1117 \le \frac{x}{2} + 1117≤2x+11 17−11≤x2+11−1117 - 11 \le \frac{x}{2} + 11 - 1117−11≤2x+11−11 6≤x26 \le \frac{x}{2}6≤2x
6≤x26 \le \frac{x}{2}6≤2x 6∗2≤x2∗26 * 2 \le \frac{x}{2} * 26∗2≤2x∗2 12≤x12 \le x12≤x
x≥12x \ge 12x≥12
The solution to the inequality is x≥12x \ge 12x≥12. On the number line, you would have a closed circle at 12 and shade to the right.
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