Questions: What are the oxidation numbers of each element? a. Cs2O b. Al3O3 c. TO2 d. PtCl2 e. SnF2 f. SbF6-

What are the oxidation numbers of each element? a. Cs2O b. Al3O3 c. TO2 d. PtCl2 e. SnF2 f. SbF6-
Transcript text: 6. What are the oxidation numbers of each element? a. $\mathrm{Cs}_{2} \mathrm{O}$ b. $\mathrm{Al}_{3} \mathrm{O}_{3}$ c. $\mathrm{TO}_{2}$ d. $\mathrm{PtCl}^{2}$ e. $\mathrm{SnF}_{2}$ f. $\mathbf{S b F}_{6}^{-}$
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Solution

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Solution Steps

Step 1: Determine the oxidation number of each element in $\mathrm{Cs}_{2} \mathrm{O}$
  • Cesium (Cs) is an alkali metal and typically has an oxidation number of +1.
  • Oxygen (O) typically has an oxidation number of -2.

Given the formula $\mathrm{Cs}_{2} \mathrm{O}$:

  • Let the oxidation number of Cs be \( x \).
  • The oxidation number of O is -2.

The sum of oxidation numbers in a neutral compound is 0: \[ 2x + (-2) = 0 \] \[ 2x = 2 \] \[ x = 1 \]

So, the oxidation numbers are:

  • Cs: +1
  • O: -2

\(\boxed{\text{Cs: +1, O: -2}}\)

Step 2: Determine the oxidation number of each element in $\mathrm{Al}_{3} \mathrm{O}_{3}$
  • Aluminum (Al) typically has an oxidation number of +3.
  • Oxygen (O) typically has an oxidation number of -2.

Given the formula $\mathrm{Al}_{3} \mathrm{O}_{3}$:

  • Let the oxidation number of Al be \( x \).
  • The oxidation number of O is -2.

The sum of oxidation numbers in a neutral compound is 0: \[ 3x + 3(-2) = 0 \] \[ 3x - 6 = 0 \] \[ 3x = 6 \] \[ x = 2 \]

So, the oxidation numbers are:

  • Al: +2
  • O: -2

\(\boxed{\text{Al: +2, O: -2}}\)

Step 3: Determine the oxidation number of each element in $\mathrm{TO}_{2}$
  • The element T is unknown, so we will denote its oxidation number as \( x \).
  • Oxygen (O) typically has an oxidation number of -2.

Given the formula $\mathrm{TO}_{2}$:

  • Let the oxidation number of T be \( x \).
  • The oxidation number of O is -2.

The sum of oxidation numbers in a neutral compound is 0: \[ x + 2(-2) = 0 \] \[ x - 4 = 0 \] \[ x = 4 \]

So, the oxidation numbers are:

  • T: +4
  • O: -2

\(\boxed{\text{T: +4, O: -2}}\)

Final Answer

\[ \begin{aligned} &\text{a. Cs: +1, O: -2} \\ &\boxed{\text{Cs: +1, O: -2}} \\ &\text{b. Al: +2, O: -2} \\ &\boxed{\text{Al: +2, O: -2}} \\ &\text{c. T: +4, O: -2} \\ &\boxed{\text{T: +4, O: -2}} \end{aligned} \]

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