Questions: Scroll down to open a Hint. The metal used in this experiment is tin (Sn) which has a density of 7.283 g / mL near room temperature. Use 7.283 g / mL as the true value for density of Sn and calculate the absolute error and relative error for density determined for each sample. Report absolute error values for A 3 in g / mL to the nearest 0.01 g / mL. Do not enter the unit. Report percent error values for A 4 in % to the nearest 0.01 %. Do not enter the % symbol.

Solution Steps

To solve this problem, we need to calculate the absolute error and relative error for the density of tin (Sn) determined for each sample. We will use the given true density value of tin, which is \(7.283 \, \text{g/mL}\).

The absolute error is the difference between the measured value and the true value. If \(d_{\text{measured}}\) is the measured density and \(d_{\text{true}} = 7.283 \, \text{g/mL}\) is the true density, the absolute error is given by:

\[ \text{Absolute Error} = |d_{\text{measured}} - d_{\text{true}}| \]

The relative error is the absolute error divided by the true value, often expressed as a percentage. It is calculated as follows:

\[ \text{Relative Error} = \left( \frac{|d_{\text{measured}} - d_{\text{true}}|}{d_{\text{true}}} \right) \times 100\% \]

For each sample, apply the formulas from Steps 1 and 2 to find the absolute and relative errors. Round the absolute error to the nearest \(0.01 \, \text{g/mL}\) and the relative error to the nearest \(0.01\%\).

Final Answer