Questions: Factor the expression that defines the function.
(m(t)=t^3+7t^2-8t-56=)
Transcript text: ALEKS - INTERMEDIATE ALGEBRA (007)
Sec 4.6 Factoring Trinomials
Question 13 of 13 (1 point) | Question Attempt: 1 of 3
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Factor the expression that defines the function.
$m(t)=t^3+7t^2-8t-56=$
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Solution
Solution Steps
To factor the given cubic polynomial \( m(t) = t^3 + 7t^2 - 8t - 56 \), we can use the Rational Root Theorem to find potential rational roots. Once a root is found, we can perform polynomial division to factor the polynomial further.
Step 1: Identify the Polynomial
We start with the polynomial given by the function:
\[
m(t) = t^3 + 7t^2 - 8t - 56
\]
Step 2: Factor the Polynomial
Using polynomial factorization techniques, we can express \( m(t) \) in a factored form. The polynomial can be factored as:
\[
m(t) = (t + 7)(t^2 - 8)
\]
Step 3: Further Factorization
The quadratic term \( t^2 - 8 \) can be further factored using the difference of squares:
\[
t^2 - 8 = t^2 - 2\sqrt{2}^2 = (t - 2\sqrt{2})(t + 2\sqrt{2})
\]
Thus, the complete factorization of \( m(t) \) is:
\[
m(t) = (t + 7)(t - 2\sqrt{2})(t + 2\sqrt{2})
\]
Final Answer
The factored form of the polynomial is:
\[
\boxed{m(t) = (t + 7)(t - 2\sqrt{2})(t + 2\sqrt{2})}
\]