Questions: Calculate the average density of the unknown liquid Report Table DD.3: Density of Unknown Liquid Table view -> List view Calculation of mass and density of unknown liquid Trial 1 Trial 2 Trial 3 --------- Mass of beaker + liquid (g) 78.779 78.755 78.693 Mass of empty beaker (g) 67.202 67.201 67.197 Mass of liquid (g) - - -2 Volume of liquid (mL) 10.00 10.00 10.00 Density of liquid (g/mL) Average density (g/mL)

Solution Steps

To find the mass of the liquid, subtract the mass of the empty beaker from the mass of the beaker with the liquid for each trial.

• Trial 1:
  \[ \text{Mass of liquid} = 78.779\, \text{g} - 67.202\, \text{g} = 11.577\, \text{g} \]

• Trial 2:
  \[ \text{Mass of liquid} = 78.755\, \text{g} - 67.201\, \text{g} = 11.554\, \text{g} \]

• Trial 3:
  \[ \text{Mass of liquid} = 78.693\, \text{g} - 67.197\, \text{g} = 11.496\, \text{g} \]

Density is calculated using the formula: \[ \text{Density} = \frac{\text{Mass of liquid}}{\text{Volume of liquid}} \]

Given that the volume of the liquid is 10.00 mL for each trial:

• Trial 1:
  \[ \text{Density} = \frac{11.577\, \text{g}}{10.00\, \text{mL}} = 1.1577\, \text{g/mL} \]

• Trial 2:
  \[ \text{Density} = \frac{11.554\, \text{g}}{10.00\, \text{mL}} = 1.1554\, \text{g/mL} \]

• Trial 3:
  \[ \text{Density} = \frac{11.496\, \text{g}}{10.00\, \text{mL}} = 1.1496\, \text{g/mL} \]

The average density is the mean of the densities from all trials.

\[ \text{Average density} = \frac{1.1577 + 1.1554 + 1.1496}{3} = \frac{3.4627}{3} = 1.1542\, \text{g/mL} \]

Final Answer