Questions: 3. Find the AROC on the interval [h, h + 2] for g(x) = 5
π
Transcript text: 3. Find the AROC on the interval [h, h + 2] for g(x) = 5
π
Solution
Solution Steps
To find the Average Rate of Change (AROC) of a constant function \( g(x) = 5\pi \) over an interval \([h, h+2]\), we use the formula for AROC: \(\frac{g(h+2) - g(h)}{(h+2) - h}\). Since \( g(x) \) is constant, \( g(h+2) = g(h) = 5\pi \), so the AROC will be zero.
Step 1: Define the Function
The function given is \( g(x) = 5\pi \), which is a constant function. This means that for any value of \( x \), the output will always be \( 5\pi \).
Step 2: Calculate \( g(h) \) and \( g(h+2) \)
For the interval \([h, h+2]\):
\( g(h) = 5\pi \)
\( g(h+2) = 5\pi \)
Step 3: Apply the AROC Formula
The Average Rate of Change (AROC) is calculated using the formula:
\[
\text{AROC} = \frac{g(h+2) - g(h)}{(h+2) - h}
\]
Substituting the values we found:
\[
\text{AROC} = \frac{5\pi - 5\pi}{(h+2) - h} = \frac{0}{2} = 0
\]
Final Answer
The Average Rate of Change on the interval \([h, h+2]\) is
\[
\boxed{0}
\]