Questions: Find the area, to the nearest square metre.

Solution Steps

The given figure consists of a rectangle and a triangle on top of it. The rectangle has a width of 15 meters and a height of 3.6 meters. The triangle has a base of 15 meters and a height of 2.4 meters.

The area of the rectangle can be calculated using the formula: \[ \text{Area}_{\text{rectangle}} = \text{width} \times \text{height} \] \[ \text{Area}_{\text{rectangle}} = 15 \, \text{m} \times 3.6 \, \text{m} = 54 \, \text{m}^2 \]

The area of the triangle can be calculated using the formula: \[ \text{Area}_{\text{triangle}} = \frac{1}{2} \times \text{base} \times \text{height} \] \[ \text{Area}_{\text{triangle}} = \frac{1}{2} \times 15 \, \text{m} \times 2.4 \, \text{m} = 18 \, \text{m}^2 \]

Add the areas of the rectangle and the triangle to get the total area: \[ \text{Total Area} = \text{Area}_{\text{rectangle}} + \text{Area}_{\text{triangle}} \] \[ \text{Total Area} = 54 \, \text{m}^2 + 18 \, \text{m}^2 = 72 \, \text{m}^2 \]

Final Answer