Questions: Question 3 For a building located in State College, PA - Tin = 70 F - Tout = 10 F - Peak heat loss - 12,000 Btu/hr - Electricity as the fuel for heating - 95% efficiency and 0.08 / kWh - HDD - 5,964 Calculate Aref Question 4 For the same question above, calculate annual heating energy use Btu Question 5 For the same question above, considering the fuel source - electricity, please calculate the energy cost () for annual heating

Question 3
For a building located in State College, PA
- Tin = 70 F
- Tout = 10 F
- Peak heat loss - 12,000 Btu/hr
- Electricity as the fuel for heating - 95% efficiency and  0.08 / kWh
- HDD - 5,964

Calculate Aref

Question 4
For the same question above, calculate annual heating energy use Btu

Question 5
For the same question above, considering the fuel source - electricity, please calculate the energy cost () for annual heating
Transcript text: Question 3 For a building located in State College, PA - $T_{\text {in }}=70 F$ - $T_{\text {out }}=10 F$ - Peak heat loss - 12,000 Btu/hr - Electricity as the fuel for heating - 95% efficiency and $\$ 0.08 / \mathrm{kWh}$ - HDD - 5,964 Calculate $\cup A_{\text {ref }}$ Question 4 For the same question above, calculate annual heating energy use Btu Question 5 For the same question above, considering the fuel source - electricity, please calculate the energy cost ( $) for annual heating
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Solution

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Solution Steps

Step 1: Understanding the Problem

We are given the following information for a building in State College, PA:

  • Indoor temperature, \( T_{\text{in}} = 70^\circ \text{F} \)
  • Outdoor temperature, \( T_{\text{out}} = 10^\circ \text{F} \)
  • Peak heat loss = 12,000 Btu/hr
  • Heating system efficiency = 95%
  • Electricity cost = \$0.08/kWh
  • Heating Degree Days (HDD) = 5,964

We need to calculate the reference area, \( \cup A_{\text{ref}} \).

Step 2: Calculate the Reference Area, \( \cup A_{\text{ref}} \)

The reference area, \( \cup A_{\text{ref}} \), is typically calculated using the formula for heat loss:

\[ Q = U \cdot A \cdot \Delta T \]

Where:

  • \( Q \) is the heat loss (Btu/hr)
  • \( U \) is the overall heat transfer coefficient (Btu/hr-ft²-°F)
  • \( A \) is the area (ft²)
  • \( \Delta T \) is the temperature difference (°F)

Given the peak heat loss is 12,000 Btu/hr and the temperature difference \( \Delta T = T_{\text{in}} - T_{\text{out}} = 70 - 10 = 60^\circ \text{F} \), we can rearrange the formula to solve for \( A \):

\[ A = \frac{Q}{U \cdot \Delta T} \]

However, without the value of \( U \), we cannot directly calculate \( A \). Therefore, we assume \( \cup A_{\text{ref}} \) is related to the peak heat loss and temperature difference, but further information or assumptions are needed to calculate it directly.

Final Answer

Since the problem does not provide enough information to calculate \( \cup A_{\text{ref}} \) directly, we cannot provide a numerical answer. Additional data or assumptions about the building's thermal properties are required.

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