Questions: If a substance is injected into the bloodstream, the percent of the maximum dosage that is present at time t is given by y=100(1-e^(-0.35(11-t))), where t is in hours, with 0 ≤ t ≤ 11. In how many hours will the percent reach 50%?
The percent will reach 50% in □ hours. (Round to the nearest whole number as needed.)
Transcript text: If a substance is injected into the bloodstream, the percent of the maximum dosage that is present at time $t$ is given by $y=100\left(1-e^{-0.35(11-t)}\right)$, where $t$ is in hours, with $0 \leq \mathrm{t} \leq 11$. In how many hours will the percent reach $50 \%$ ?
The percent will reach $50 \%$ in $\square$ hours.
(Round to the nearest whole number as needed.)
Solution
Solution Steps
To find the time \( t \) when the percent of the maximum dosage reaches 50%, we need to solve the equation \( y = 100\left(1-e^{-0.35(11-t)}\right) \) for \( y = 50 \). This involves isolating \( t \) in the equation and solving for it. We will use Python to perform the calculation and round the result to the nearest whole number.
Step 1: Set Up the Equation
We start with the equation that describes the percent of the maximum dosage present at time \( t \):
\[
y = 100\left(1 - e^{-0.35(11 - t)}\right)
\]
We need to find \( t \) when \( y = 50 \).
Step 2: Substitute and Rearrange
Substituting \( y = 50 \) into the equation gives:
\[
50 = 100\left(1 - e^{-0.35(11 - t)}\right)
\]
Dividing both sides by 100:
\[
0.5 = 1 - e^{-0.35(11 - t)}
\]
Rearranging this, we have:
\[
e^{-0.35(11 - t)} = 0.5
\]
Step 3: Solve for \( t \)
Taking the natural logarithm of both sides:
\[
-0.35(11 - t) = \ln(0.5)
\]
Solving for \( t \):
\[
11 - t = -\frac{\ln(0.5)}{0.35}
\]
Thus,
\[
t = 11 + \frac{\ln(0.5)}{0.35}
\]
Step 4: Calculate \( t \)
Calculating the value gives:
\[
t \approx 12.9804
\]
Rounding to the nearest whole number results in:
\[
t \approx 13
\]
Final Answer
The percent will reach \( 50\% \) in \( \boxed{13} \) hours.