Questions: The temperature of a sample of copper increased by 23.5°C when 269 J of heat was applied. What is the mass of the sample? Substance Specific heat J /(g · °C) ------ lead 0.128 silver 0.235 copper 0.385 iron 0.449 aluminum 0.903 m= g

Solution Steps

We are given the following information:

• Heat applied, \( Q = 269 \, \text{J} \)
• Temperature change, \( \Delta T = 23.5^{\circ} \text{C} \)
• Specific heat of copper, \( c = 0.385 \, \text{J/g}^{\circ} \text{C} \)

The formula for heat transfer is: \[ Q = mc\Delta T \] where \( m \) is the mass of the sample, \( c \) is the specific heat, and \( \Delta T \) is the change in temperature.

Rearrange the formula to solve for mass \( m \): \[ m = \frac{Q}{c\Delta T} \]

Substitute the given values into the equation: \[ m = \frac{269 \, \text{J}}{0.385 \, \text{J/g}^{\circ} \text{C} \times 23.5^{\circ} \text{C}} \]

Perform the calculation: \[ m = \frac{269}{0.385 \times 23.5} = \frac{269}{9.0475} \approx 29.74 \, \text{g} \]

Final Answer