Questions: In one city, 47.5% of adults are female, 10.2% of adults are left-handed, and 4.8% are left-handed females. For an adult selected at random from the city, let F= event the person is female and let L= event the person is left-handed. Find P(F or L). Round approximations to three decimal places. A. 0.529 B. 0.6245 C. 0.482 D. 0.679 E. 0.577

Solution Steps

To find the probability of either event F (female) or event L (left-handed) occurring, we use the formula for the probability of the union of two events: \( P(F \cup L) = P(F) + P(L) - P(F \cap L) \). We are given \( P(F) = 0.475 \), \( P(L) = 0.102 \), and \( P(F \cap L) = 0.048 \). Substitute these values into the formula to find \( P(F \cup L) \).

We are given the following probabilities:

• \( P(F) = 0.475 \) (the probability that an adult is female)
• \( P(L) = 0.102 \) (the probability that an adult is left-handed)
• \( P(F \cap L) = 0.048 \) (the probability that an adult is both female and left-handed)

To find the probability of either event \( F \) or event \( L \) occurring, we use the formula for the union of two events: \[ P(F \cup L) = P(F) + P(L) - P(F \cap L) \]

Substituting the given values into the formula: \[ P(F \cup L) = 0.475 + 0.102 - 0.048 \]

Calculating the above expression: \[ P(F \cup L) = 0.475 + 0.102 - 0.048 = 0.529 \]

Final Answer