Questions: Let A = [ [1/4, 0, 0], [0, 1/4, 0], [0, 0, 1/4] ], u = [4, 12, -8], and v = [k, f, h]. Define T: R^3 -> R^3 by T(x) = Ax. Find T(u) and T(v).
T(u) = □
(Simplify your answer. Use integers or fractions for any numbers in the expression.)
Transcript text: Let $A=\left[\begin{array}{lll}\frac{1}{4} & 0 & 0 \\ 0 & \frac{1}{4} & 0 \\ 0 & 0 & \frac{1}{4}\end{array}\right], u=\left[\begin{array}{r}4 \\ 12 \\ -8\end{array}\right]$, and $v=\left[\begin{array}{l}k \\ f \\ h\end{array}\right]$. Define $T: R^{3} \rightarrow R^{3}$ by $T(x)=A x$. Find $T(u)$ and $T(v)$.
\[
\mathrm{T}(\mathbf{u})=\square
\]
(Simplify your answer. Use integers or fractions for any numbers in the expression.)
Solution
Solution Steps
Step 1: Compute \( T(u) \) by multiplying matrix \( A \) with vector \( u \)
Step 3: Compute \( T(v) \) by multiplying matrix \( A \) with vector \( v \)
Given:
\[
v = \begin{bmatrix}
k \\
f \\
h
\end{bmatrix}
\]
The transformation \( T(v) \) is calculated as:
\[
T(v) = A \cdot v = \begin{bmatrix}
\frac{1}{4} \cdot k + 0 \cdot f + 0 \cdot h \\
0 \cdot k + \frac{1}{4} \cdot f + 0 \cdot h \\
0 \cdot k + 0 \cdot f + \frac{1}{4} \cdot h
\end{bmatrix}
\]
Step 4: Simplify the multiplication for \( T(v) \)