Questions: Solve the following system of linear equations by graphing:
-6x + 3y = 27
-6x + 3y = 9
Graph the linear equations by writing the equations in slope-intercept form:
y = x +
y = x +
Transcript text: Solve the following system of linear equations by graphing:
\[
\begin{array}{l}
-6 x+3 y=27 \\
-6 x+3 y=9
\end{array}
\]
Graph the linear equations by writing the equations in slope-intercept form:
\[
\begin{array}{l}
y=\square x+\square \\
y=\square x+\square
\end{array}
\]
Solution
Solution Steps
Step 1: Convert the first equation to slope-intercept form
The first equation is \(-6x + 3y = 27\). To convert it to slope-intercept form (\(y = mx + b\)), solve for \(y\):
\[
-6x + 3y = 27
\]
Add \(6x\) to both sides:
\[
3y = 6x + 27
\]
Divide by 3:
\[
y = 2x + 9
\]
Step 2: Convert the second equation to slope-intercept form
The second equation is \(-6x + 3y = 9\). To convert it to slope-intercept form (\(y = mx + b\)), solve for \(y\):
\[
-6x + 3y = 9
\]
Add \(6x\) to both sides:
\[
3y = 6x + 9
\]
Divide by 3:
\[
y = 2x + 3
\]
Step 3: Graph the equations
Graph the two equations \(y = 2x + 9\) and \(y = 2x + 3\) on the coordinate plane.
Final Answer
The system of equations has no solution because the lines are parallel and do not intersect.