Questions: Which element is reduced in the reaction represented by the equation: 2 Mg + O2 -> 2 MgO if Mg goes from 0 to +2 and O goes from 0 to -2?
Transcript text: Which element is reduced in the reaction represented by the equation: $2 \mathrm{Mg}+\mathrm{O}_{2} \rightarrow 2 \mathrm{MgO}$ if Mg goes from 0 to +2 and O goes from 0 to $-2$?
Solution
Solution Steps
Step 1: Identify Oxidation States
First, we need to identify the oxidation states of magnesium (Mg) and oxygen (O) in the reactants and products.
In the reactants:
Mg is in the elemental form, so its oxidation state is 0.
O is in the elemental form (\(\mathrm{O}_2\)), so its oxidation state is 0.
In the products:
Mg in \(\mathrm{MgO}\) has an oxidation state of +2.
O in \(\mathrm{MgO}\) has an oxidation state of -2.
Step 2: Determine Changes in Oxidation States
Next, we determine the changes in oxidation states for each element.
Mg goes from 0 to +2, which means it loses electrons and is oxidized.
O goes from 0 to -2, which means it gains electrons and is reduced.
Step 3: Identify the Reduced Element
The element that gains electrons is the one that is reduced. In this reaction, oxygen (O) gains electrons, changing its oxidation state from 0 to -2.