Questions: Find the limits in a) through c) below for the function f(x) = (x^2 - 11x + 10) / (x + 10). Use -∞ and ∞ when appropriate. A. lim f(x) = -∞ x -> -10^- (Simplify your answer.) B. The limit does not exist and is neither -∞ nor ∞. b) Select the correct choice below and fill in any answer boxes in your choice. A. lim x -> -10^+ f(x) = ∞ x -> -10^+ (Simplify your answer.) B. The limit does not exist and is neither -∞ nor ∞. c) Select the correct choice below and fill in any answer boxes in your choice. A. lim x -> -10 f(x) = (Simplify your answer.)

Find the limits in a) through c) below for the function f(x) = (x^2 - 11x + 10) / (x + 10). Use -∞ and ∞ when appropriate.
A. lim f(x) = -∞
x -> -10^-
(Simplify your answer.)
B. The limit does not exist and is neither -∞ nor ∞.
b) Select the correct choice below and fill in any answer boxes in your choice.
A. lim x -> -10^+ f(x) = ∞
x -> -10^+
(Simplify your answer.)
B. The limit does not exist and is neither -∞ nor ∞.
c) Select the correct choice below and fill in any answer boxes in your choice.
A. lim x -> -10 f(x) = 
(Simplify your answer.)
Transcript text: Find the limits in a ) through c ) below for the function $f(x)=\frac{x^{2}-11 x+10}{x+10}$. Use $-\infty$ and $\infty$ when appropriate. A. $\quad \lim f(x)=-\infty$ $\square$ \[ x \rightarrow-10^{-} \] (Simplify your answer.) B. The limit does not exist and is neither $-\infty$ nor $\infty$. b) Select the correct choice below and fill in any answer boxes in your choice. A. $\lim _{x \rightarrow-10^{+}} f(x)=\infty$ \[ x \rightarrow-10^{+} \] $\square$ (Simplify your answer.) B. The limit does not exist and is neither $-\infty$ nor $\infty$. c) Select the correct choice below and fill in any answer boxes in your choice. A. $\lim _{x \rightarrow-10} f(x)=$ $\square$ (Simplify your answer.)
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Solution

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Solution Steps

To find the limits of the function \( f(x) = \frac{x^2 - 11x + 10}{x + 10} \) as \( x \) approaches specific values, we need to analyze the behavior of the function around these points.

A. As \( x \to -10^- \), we approach -10 from the left. We need to check the sign of the numerator and denominator to determine if the function approaches \(-\infty\) or \(\infty\).

B. As \( x \to -10^+ \), we approach -10 from the right. Again, we check the sign of the numerator and denominator to determine the behavior of the function.

C. As \( x \to -10 \), we need to determine if the limit exists by checking if the left-hand limit and right-hand limit are equal.

Step 1: Analyze the Function

The function given is \( f(x) = \frac{x^2 - 11x + 10}{x + 10} \). We need to find the limits as \( x \) approaches \(-10\) from different directions.

Step 2: Limit as \( x \to -10^- \)

As \( x \) approaches \(-10\) from the left (\( x \to -10^- \)), the denominator \( x + 10 \) approaches zero from the negative side. The numerator \( x^2 - 11x + 10 \) evaluates to a positive number near \( x = -10 \). Therefore, the function approaches \(-\infty\).

Step 3: Limit as \( x \to -10^+ \)

As \( x \) approaches \(-10\) from the right (\( x \to -10^+ \)), the denominator \( x + 10 \) approaches zero from the positive side. The numerator remains positive near \( x = -10 \). Therefore, the function approaches \(\infty\).

Step 4: Limit as \( x \to -10 \)

The limit as \( x \to -10 \) does not exist because the left-hand limit and the right-hand limit are not equal. Specifically, the left-hand limit is \(-\infty\) and the right-hand limit is \(\infty\).

Final Answer

A. \(\boxed{-\infty}\)

B. \(\boxed{\infty}\)

C. The limit does not exist.

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