Questions: Find the limits in a) through c) below for the function f(x) = (x^2 - 11x + 10) / (x + 10). Use -∞ and ∞ when appropriate.
A. lim f(x) = -∞
x -> -10^-
(Simplify your answer.)
B. The limit does not exist and is neither -∞ nor ∞.
b) Select the correct choice below and fill in any answer boxes in your choice.
A. lim x -> -10^+ f(x) = ∞
x -> -10^+
(Simplify your answer.)
B. The limit does not exist and is neither -∞ nor ∞.
c) Select the correct choice below and fill in any answer boxes in your choice.
A. lim x -> -10 f(x) =
(Simplify your answer.)
Transcript text: Find the limits in a ) through c ) below for the function $f(x)=\frac{x^{2}-11 x+10}{x+10}$. Use $-\infty$ and $\infty$ when appropriate.
A. $\quad \lim f(x)=-\infty$
$\square$
\[
x \rightarrow-10^{-}
\]
(Simplify your answer.)
B. The limit does not exist and is neither $-\infty$ nor $\infty$.
b) Select the correct choice below and fill in any answer boxes in your choice.
A. $\lim _{x \rightarrow-10^{+}} f(x)=\infty$
\[
x \rightarrow-10^{+}
\]
$\square$
(Simplify your answer.)
B. The limit does not exist and is neither $-\infty$ nor $\infty$.
c) Select the correct choice below and fill in any answer boxes in your choice.
A. $\lim _{x \rightarrow-10} f(x)=$ $\square$
(Simplify your answer.)
Solution
Solution Steps
To find the limits of the function \( f(x) = \frac{x^2 - 11x + 10}{x + 10} \) as \( x \) approaches specific values, we need to analyze the behavior of the function around these points.
A. As \( x \to -10^- \), we approach -10 from the left. We need to check the sign of the numerator and denominator to determine if the function approaches \(-\infty\) or \(\infty\).
B. As \( x \to -10^+ \), we approach -10 from the right. Again, we check the sign of the numerator and denominator to determine the behavior of the function.
C. As \( x \to -10 \), we need to determine if the limit exists by checking if the left-hand limit and right-hand limit are equal.
Step 1: Analyze the Function
The function given is \( f(x) = \frac{x^2 - 11x + 10}{x + 10} \). We need to find the limits as \( x \) approaches \(-10\) from different directions.
Step 2: Limit as \( x \to -10^- \)
As \( x \) approaches \(-10\) from the left (\( x \to -10^- \)), the denominator \( x + 10 \) approaches zero from the negative side. The numerator \( x^2 - 11x + 10 \) evaluates to a positive number near \( x = -10 \). Therefore, the function approaches \(-\infty\).
Step 3: Limit as \( x \to -10^+ \)
As \( x \) approaches \(-10\) from the right (\( x \to -10^+ \)), the denominator \( x + 10 \) approaches zero from the positive side. The numerator remains positive near \( x = -10 \). Therefore, the function approaches \(\infty\).
Step 4: Limit as \( x \to -10 \)
The limit as \( x \to -10 \) does not exist because the left-hand limit and the right-hand limit are not equal. Specifically, the left-hand limit is \(-\infty\) and the right-hand limit is \(\infty\).