Questions: If mass 33 kg and mass 109 kg are placed on the left and right side of a seesaw of length 1 m respectively, where must the fulcrum be placed from the left end such that the seesaw remains level? enter only a numerical answer. Do not enter units, Doing so would result in wrong answer.

If mass 33 kg and mass 109 kg are placed on the left and right side of a seesaw of length 1 m respectively, where must the fulcrum be placed from the left end such that the seesaw remains level? enter only a numerical answer. Do not enter units, Doing so would result in wrong answer.

Transcript text: If mass 33 kg and mass 109 kg are placed on the left and right side of a seesaw of length 1 m respectively, where must the fulcrum be placed from the left end such that the seesaw remains level? enter only a numerical answer. Do not enter units, Doing so would result in wrong answer.

Solution

Solution Steps

Step 1: Understand the Problem

We are given a seesaw of length \(L\) with two masses, \(m_1\) and \(m_2\), placed at the left and right ends respectively. We need to find the position \(x\) from the left end where the fulcrum must be placed to balance the seesaw.

Step 2: Apply the Principle of Moments

The seesaw will balance when the moments (torque) about the fulcrum for both masses are equal. The moment is the product of the force (due to gravity) and the distance from the pivot. Thus, we have \(m_1 \cdot x = m_2 \cdot (L - x)\).

Step 3: Solve for \(x\)

Rearranging the equation \(m_1 \cdot x = m_2 \cdot (L - x)\) gives us \(x = \frac{m_2 \cdot L}{m_1 + m_2}\).

Step 4: Calculate \(x\)

Substituting the given values \(m_1 = 33\), \(m_2 = 109\), and \(L = 1\) into the formula, we get \(x = \frac{109 \cdot 1}{33 + 109}\) = 0.77.