Questions: According to the equation (2 A(s) + 2 B(aq) → 2 C(aq) + 3 D(g)), if 5.870 grams of A fully reacted in 252.555 mL of B, what is the concentration, in M, of B? The molar mass of A is 64.859 g/mol.

Solution Steps

First, we need to determine the number of moles of A that reacted. We use the molar mass of A to convert grams to moles.

\[ \text{Moles of A} = \frac{\text{Mass of A}}{\text{Molar mass of A}} = \frac{5.870 \, \text{g}}{64.859 \, \text{g/mol}} = 0.0905 \, \text{mol} \]

According to the balanced chemical equation, 2 moles of A react with 2 moles of B. Therefore, the moles of B required are equal to the moles of A.

\[ \text{Moles of B} = 0.0905 \, \text{mol} \]

The concentration of B is given by the number of moles of B divided by the volume of the solution in liters. First, convert the volume from milliliters to liters.

\[ \text{Volume of B} = 252.555 \, \text{mL} = 0.2526 \, \text{L} \]

Now, calculate the concentration:

\[ \text{Concentration of B} = \frac{\text{Moles of B}}{\text{Volume of B}} = \frac{0.0905 \, \text{mol}}{0.2526 \, \text{L}} = 0.3583 \, \text{M} \]

Final Answer