Questions: Multiply and simplify. [ (x^2-7 x-18)/(2 x^2-162) cdot (x^2+18 x+81)/(2 x^2+22 x+36) ]

Multiply and simplify.
[
(x^2-7 x-18)/(2 x^2-162) cdot (x^2+18 x+81)/(2 x^2+22 x+36)
]
Transcript text: Multiply and simplify. \[ \frac{x^{2}-7 x-18}{2 x^{2}-162} \cdot \frac{x^{2}+18 x+81}{2 x^{2}+22 x+36} \]
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Solution

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Solution Steps

To solve the given problem, we need to follow these steps:

  1. Factorize the numerators and denominators of both fractions.
  2. Simplify the fractions by canceling out common factors.
  3. Multiply the simplified fractions.
Step 1: Factorization

We start by factorizing the expressions in the problem:

  1. The numerator x27x18 x^2 - 7x - 18 factors to (x9)(x+2) (x - 9)(x + 2) .
  2. The denominator 2x2162 2x^2 - 162 factors to 2(x9)(x+9) 2(x - 9)(x + 9) .
  3. The numerator x2+18x+81 x^2 + 18x + 81 factors to (x+9)2 (x + 9)^2 .
  4. The denominator 2x2+22x+36 2x^2 + 22x + 36 factors to 2(x+2)(x+9) 2(x + 2)(x + 9) .
Step 2: Simplification of Fractions

We can now express the fractions using their factored forms:

(x9)(x+2)2(x9)(x+9)(x+9)22(x+2)(x+9) \frac{(x - 9)(x + 2)}{2(x - 9)(x + 9)} \cdot \frac{(x + 9)^2}{2(x + 2)(x + 9)}

Step 3: Canceling Common Factors

Next, we simplify the expression by canceling out the common factors:

  • The (x9) (x - 9) in the numerator and denominator cancels.
  • The (x+2) (x + 2) in the numerator and denominator cancels.
  • One (x+9) (x + 9) in the numerator cancels with one in the denominator.

This leaves us with:

(x+9)4 \frac{(x + 9)}{4}

Final Answer

Thus, the simplified result of the multiplication is:

14 \boxed{\frac{1}{4}}

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