Questions: The mean monthly rent of students at Oxnard University is 970 with a standard deviation of 204. (a) John's rent is 1,390. What is his standardized z-score? (Round your answer to 3 decimal places.)

The mean monthly rent of students at Oxnard University is 970 with a standard deviation of 204. (a) John's rent is 1,390. What is his standardized z-score? (Round your answer to 3 decimal places.)
Transcript text: The mean monthly rent of students at Oxnard University is $\$ 970$ with a standard deviation of $\$ 204$. (a) John's rent is $\$ 1,390$. What is his standardized $z$-score? (Round your answer to 3 decimal places.)
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the Given Values

We are given the following values:

  • Mean monthly rent, \(\mu = 970\)
  • Standard deviation, \(\sigma = 204\)
  • John's rent, \(X = 1390\)
Step 2: Calculate the Z-Score

The formula for calculating the standardized \(z\)-score is:

\[ z = \frac{X - \mu}{\sigma} \]

Substituting the given values:

\[ z = \frac{1390 - 970}{204} = \frac{420}{204} \approx 2.0588 \]

Step 3: Round the Z-Score

Round the \(z\)-score to three decimal places:

\[ z \approx 2.059 \]

Final Answer

\(\boxed{z \approx 2.059}\)

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
the Cold War I Exam Which group of countries occupied the four military zones in Germany after World War II? Italy, Japan, Greece, Turkey United States, France, Great Britain, Soviet Union
failedAnswered
The prime mover of hip extension is the pectineus gluteus maximus gracilis adductor magnus
failedAnswered
Administrative Court Judges typically have judges. a. less b. more c. about the same
failedAnswered
1. Make a well-labeled diagram of your actual gel results below. The wells are indicated by the boxes. Discussion 1. The Introduction mentioned that there are three possible results when testing a given DNA sample. Each possible result is run in its own lane of an agarose gel. Describe and draw what these three lanes would look like. The three possible results represent different genotypes for a particular DNA sequence. Homozygous present indicates two copies of the allele, homozygous absent indicates no copies, and heterozygous indicates one copy of the allele. The gel electrophoresis separates the DNA fragments by size. The presence or absence of the allele affects the size of the DNA fragment and thus its migration through the gel, resulting in distinct band patterns for each genotype. It is expected that different cell types from the same patient would show the same banding pattern reflecting the same genotype. 2. Based on the expected results for the gel (NOT the actual results you sketched above), what can you conclude about the genotype of the patient in her different cell types? Explain your answer.
failedAnswered
Identify the function type that best models the data. x y [Select ] --------- 4 2 8 6 12 18 16 54 x y ------ 10 6 20 13 30 17 40 20 x y ------ 2 12 6 18 12 21 18 27