Questions: Atoms, Ions and Molecules Deducing the ions in a binary ionic compound from its empirical formula 3 / 5 Complete the table below by writing the symbols for the cation and anion that make up each ionic compound. The first row has been completed for you. ionic compound cation anion --------- NaCl Na+ Cl- AuF3 AuBr MnO2 CrI3

Atoms, Ions and Molecules
Deducing the ions in a binary ionic compound from its empirical formula
3 / 5

Complete the table below by writing the symbols for the cation and anion that make up each ionic compound. The first row has been completed for you.

ionic compound  cation  anion
---------
NaCl  Na+  Cl-
AuF3    
AuBr    
MnO2    
CrI3
Transcript text: Atoms, Ions and Molecules Deducing the ions in a binary ionic compound from its empirical formula $3 / 5$ Complete the table below by writing the symbols for the cation and anion that make up each ionic compound. The first row has been completed for you. \begin{tabular}{|c|c|c|} \hline \begin{tabular}{c} ionic \\ compound \end{tabular} & cation & anion \\ \hline NaCl & $\mathrm{Na}^{+}$ & $\mathrm{Cl}^{-}$ \\ \hline $\mathrm{AuF}_{3}$ & $\square$ & $\square$ \\ \hline AuBr & $\square$ & $\square$ \\ \hline $\mathrm{MnO}_{2}$ & $\square$ & $\square$ \\ \hline $\mathrm{CrI}_{3}$ & $\square$ & $\square$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Identify the cation and anion in \(\mathrm{AuF}_{3}\)
  • The cation is \(\mathrm{Au}^{3+}\)
  • The anion is \(\mathrm{F}^{-}\)
Step 2: Identify the cation and anion in \(\mathrm{AuBr}\)
  • The cation is \(\mathrm{Au}^{+}\)
  • The anion is \(\mathrm{Br}^{-}\)
Step 3: Identify the cation and anion in \(\mathrm{MnO}_{2}\)
  • The cation is \(\mathrm{Mn}^{4+}\)
  • The anion is \(\mathrm{O}^{2-}\)

Final Answer

For \(\mathrm{AuF}_{3}\): Cation: \(\mathrm{Au}^{3+}\), Anion: \(\mathrm{F}^{-}\) \\ For \(\mathrm{AuBr}\): Cation: \(\mathrm{Au}^{+}\), Anion: \(\mathrm{Br}^{-}\) \\ For \(\mathrm{MnO}_{2}\): Cation: \(\mathrm{Mn}^{4+}\), Anion: \(\mathrm{O}^{2-}\) \\ For \(\mathrm{CrI}_{3}\): Cation: \(\mathrm{Cr}^{3+}\), Anion: \(\mathrm{I}^{-}\)

Thus, the final boxed answers are: \[ \boxed{\text{For } \mathrm{AuF}_{3}: \mathrm{Au}^{3+}, \mathrm{F}^{-}} \] \[ \boxed{\text{For } \mathrm{AuBr}: \mathrm{Au}^{+}, \mathrm{Br}^{-}} \] \[ \boxed{\text{For } \mathrm{MnO}_{2}: \mathrm{Mn}^{4+}, \mathrm{O}^{2-}} \] \[ \boxed{\text{For } \mathrm{CrI}_{3}: \mathrm{Cr}^{3+}, \mathrm{I}^{-}} \]

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