Questions: Problem 14.7 The relative rates of the reaction A+B → products in vessels (1)-(4) are 1: 1: 4: 4. Red spheres represent A molecules, and blue spheres represent B molecules. (Figure 1 ) Part A What is the order of the reaction in A? zeroth-order first-order second-order third-order Submit Request Answer Part B

Problem 14.7

The relative rates of the reaction A+B → products in vessels (1)-(4) are 1: 1: 4: 4. Red spheres represent A molecules, and blue spheres represent B molecules. (Figure 1 ) Part A

What is the order of the reaction in A? zeroth-order first-order second-order third-order Submit Request Answer Part B

Transcript text: Problem 14.7 The relative rates of the reaction $\mathrm{A}+\mathrm{B} \rightarrow$ products in vessels (1)-(4) are $1: 1: 4: 4$. Red spheres represent $A$ molecules, and blue spheres represent B molecules. (Figure 1 ) Part A What is the order of the reaction in A? zeroth-order first-order second-order third-order Submit Request Answer Part B

Solution

Solution Steps

Step 1: Understanding the Problem

We are given the relative rates of a reaction $\mathrm{A} + \mathrm{B} \rightarrow$ products in four different vessels. The rates are in the ratio $1: 1: 4: 4$. We need to determine the order of the reaction with respect to $\mathrm{A}$.

Step 2: Analyzing the Given Data

The relative rates suggest that the reaction rate changes under different conditions. Since the rates are given as $1: 1: 4: 4$, we can infer that the concentration of $\mathrm{A}$ or $\mathrm{B}$ is changing in such a way that it affects the rate.

Step 3: Determining the Order of Reaction with Respect to A

To determine the order of the reaction with respect to $\mathrm{A}$, we need to see how the rate changes with the concentration of $\mathrm{A}$. If the rate quadruples when the concentration of $\mathrm{A}$ is doubled, it suggests a second-order reaction with respect to $\mathrm{A}$.