To solve the equation \(2|x+3|+4=34\), we first isolate the absolute value expression. Subtract 4 from both sides to get \(2|x+3| = 30\). Then, divide both sides by 2 to obtain \(|x+3| = 15\). This absolute value equation implies two possible linear equations: \(x+3 = 15\) and \(x+3 = -15\). Solve each equation separately to find the values of \(x\).
Step 1: Isolate the Absolute Value
Starting with the equation:
\[
2|x+3| + 4 = 34
\]
we first subtract 4 from both sides:
\[
2|x+3| = 30
\]
Step 2: Solve for the Absolute Value
Next, we divide both sides by 2:
\[
|x+3| = 15
\]
Step 3: Set Up the Linear Equations
The absolute value equation \( |x+3| = 15 \) leads to two cases:
\( x + 3 = 15 \)
\( x + 3 = -15 \)
Step 4: Solve Each Case
For the first case:
\[
x + 3 = 15 \implies x = 15 - 3 = 12
\]
For the second case:
\[
x + 3 = -15 \implies x = -15 - 3 = -18
\]
Final Answer
The solutions to the equation are:
\[
\boxed{x = 12} \quad \text{and} \quad \boxed{x = -18}
\]