Questions: Find the indicated probability using the standard normal distribution.
P(z<1.52)
Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table.
P(z<1.52)= (Round to four decimal places as needed.)
Transcript text: Find the indicated probability using the standard normal distribution.
\[
P(z<1.52)
\]
Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table.
$\mathrm{P}(\mathrm{z}<1.52)=$ $\square$ (Round to four decimal places as needed.)
Solution
Solution Steps
Step 1: Define the Probability Expression
To find the probability \( P(z < 1.52) \) using the standard normal distribution, we can express it in terms of the cumulative distribution function \( \Phi \):
\[
P(z < 1.52) = \Phi(1.52) - \Phi(-\infty)
\]
Step 2: Evaluate the Cumulative Distribution Function
Since \( \Phi(-\infty) = 0 \), the expression simplifies to:
\[
P(z < 1.52) = \Phi(1.52)
\]
Step 3: Calculate the Probability
From the calculations, we find that:
\[
\Phi(1.52) \approx 0.9357
\]
Final Answer
Thus, the probability that \( z \) is less than \( 1.52 \) is:
\[
\boxed{P(z < 1.52) = 0.9357}
\]