Questions: Find the indicated probability using the standard normal distribution. P(z<1.52) Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. P(z<1.52)= (Round to four decimal places as needed.)

Find the indicated probability using the standard normal distribution.
P(z<1.52)

Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table.
P(z<1.52)= (Round to four decimal places as needed.)
Transcript text: Find the indicated probability using the standard normal distribution. \[ P(z<1.52) \] Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. $\mathrm{P}(\mathrm{z}<1.52)=$ $\square$ (Round to four decimal places as needed.)
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Solution

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Solution Steps

Step 1: Define the Probability Expression

To find the probability \( P(z < 1.52) \) using the standard normal distribution, we can express it in terms of the cumulative distribution function \( \Phi \): \[ P(z < 1.52) = \Phi(1.52) - \Phi(-\infty) \]

Step 2: Evaluate the Cumulative Distribution Function

Since \( \Phi(-\infty) = 0 \), the expression simplifies to: \[ P(z < 1.52) = \Phi(1.52) \]

Step 3: Calculate the Probability

From the calculations, we find that: \[ \Phi(1.52) \approx 0.9357 \]

Final Answer

Thus, the probability that \( z \) is less than \( 1.52 \) is: \[ \boxed{P(z < 1.52) = 0.9357} \]

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