To find the first derivative f′(x) f^{\prime}(x) f′(x) of the function f(x)=(x2+4)6 f(x) = (x^2 + 4)^6 f(x)=(x2+4)6, we apply the chain rule. The result is: f′(x)=12x(x2+4)5 f^{\prime}(x) = 12x(x^2 + 4)^5 f′(x)=12x(x2+4)5
Next, we differentiate the first derivative f′(x) f^{\prime}(x) f′(x) to obtain the second derivative f′′(x) f^{\prime \prime}(x) f′′(x). The calculation yields: f′′(x)=120x2(x2+4)4+12(x2+4)5 f^{\prime \prime}(x) = 120x^2(x^2 + 4)^4 + 12(x^2 + 4)^5 f′′(x)=120x2(x2+4)4+12(x2+4)5
Thus, the second derivative of the function is: f′′(x)=120x2(x2+4)4+12(x2+4)5 \boxed{f^{\prime \prime}(x) = 120x^2(x^2 + 4)^4 + 12(x^2 + 4)^5} f′′(x)=120x2(x2+4)4+12(x2+4)5
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