Questions: Jen made a scale drawing of a county park. The scale of the drawing was 13 inches : 6 yards. The picnic area is 42 yards wide in real life. How wide is the picnic area in the drawing? inches

Solution Steps

To solve this problem, we need to use the given scale to convert the real-life width of the picnic area into the width in the drawing. The scale is given as 13 inches : 6 yards. We can set up a proportion to find the width in the drawing.

The given scale is \( 13 \) inches : \( 6 \) yards. This means that \( 13 \) inches on the drawing represents \( 6 \) yards in real life.

We need to find the width of the picnic area in the drawing. Let \( x \) be the width in inches on the drawing. We can set up the proportion: \[ \frac{13 \text{ inches}}{6 \text{ yards}} = \frac{x \text{ inches}}{42 \text{ yards}} \]

To solve for \( x \), we cross-multiply and solve for \( x \): \[ 13 \times 42 = 6 \times x \] \[ 546 = 6x \] \[ x = \frac{546}{6} \] \[ x = 91.0 \]

Final Answer