Questions: Find the average rate of change of the function (f(x)=5x) from (x1=0) to (x2=4).
The average rate of change is (square) (Simplify your answer.)
Transcript text: Find the average rate of change of the function $f(x)=5 x$ from $x_{1}=0$ to $x_{2}=4$.
The average rate of change is $\square$ (Simplify your answer.)
Solution
Solution Steps
Step 1: Define the Function and Interval
We are given the function \( f(x) = 5x \) and the interval from \( x_1 = 0 \) to \( x_2 = 4 \).
Step 2: Calculate Function Values at Endpoints
Evaluate the function at the endpoints of the interval:
\[
f(x_1) = f(0) = 5 \cdot 0 = 0
\]
\[
f(x_2) = f(4) = 5 \cdot 4 = 20
\]
Step 3: Calculate the Average Rate of Change
The average rate of change of the function over the interval \([x_1, x_2]\) is given by:
\[
\text{Average Rate of Change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}
\]
Substitute the values we calculated:
\[
\text{Average Rate of Change} = \frac{20 - 0}{4 - 0} = \frac{20}{4} = 5
\]
Final Answer
The average rate of change of the function \( f(x) = 5x \) from \( x_1 = 0 \) to \( x_2 = 4 \) is:
\[
\boxed{5}
\]