Questions: Find the linear speed ν for the following. a point on the edge of a flywheel of radius 2 m , rotating 44 times per min The linear speed ν for a point on the edge of a flywheel of radius 2 m , rotating 44 times per min is (Simplify your answer. Type an exact answer, using π as needed. Use integers or fractions for any numbers in the expression.)

Find the linear speed ν for the following. a point on the edge of a flywheel of radius 2 m , rotating 44 times per min

The linear speed ν for a point on the edge of a flywheel of radius 2 m , rotating 44 times per min is (Simplify your answer. Type an exact answer, using π as needed. Use integers or fractions for any numbers in the expression.)
Transcript text: Find the linear speed $\nu$ for the following. a point on the edge of a flywheel of radius 2 m , rotating 44 times per min The linear speed $\nu$ for a point on the edge of a flywheel of radius 2 m , rotating 44 times per min is $\square$ $\square$ (Simplify your answer. Type an exact answer, using $\pi$ as needed. Use integers or fractions for any numbers in the expression.)
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Solution

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Solution Steps

Step 1: Understand the Problem

We need to find the linear speed \(\nu\) of a point on the edge of a flywheel. The flywheel has a radius of 2 meters and rotates 44 times per minute.

Step 2: Calculate the Circumference of the Flywheel

The circumference \(C\) of a circle (or flywheel in this case) is given by the formula: \[ C = 2\pi r \] where \(r\) is the radius. Substituting \(r = 2\) meters, we get: \[ C = 2\pi \times 2 = 4\pi \text{ meters} \]

Step 3: Calculate the Linear Speed

The linear speed \(\nu\) is the distance traveled per unit of time. Since the flywheel rotates 44 times per minute, the point on the edge travels 44 circumferences per minute. Therefore, the linear speed is: \[ \nu = 44 \times 4\pi = 176\pi \text{ meters per minute} \]

Final Answer

The linear speed \(\nu\) of a point on the edge of the flywheel is \(\boxed{176\pi}\) meters per minute.

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