Questions: Select the correct answer. Consider function f. f(x) = √(x-2) Which graph represents function f? A. W B. X C. Y D. z

Solution Steps

The function given is \( f(x) = \sqrt{x - 2} \). The expression inside the square root must be non-negative for the function to be real-valued. Therefore, \( x - 2 \geq 0 \), which simplifies to \( x \geq 2 \).

Since \( x \geq 2 \), the function starts at \( x = 2 \). At \( x = 2 \), \( f(2) = \sqrt{2 - 2} = \sqrt{0} = 0 \). So, the point (2, 0) is on the graph.

The function \( f(x) = \sqrt{x - 2} \) is a square root function shifted 2 units to the right. The graph will start at (2, 0) and increase slowly as \( x \) increases.

Final Answer