Questions: Select the correct answer. Consider function f. f(x) = √(x-2) Which graph represents function f? A. W B. X C. Y D. z

Solution Steps

The function given is $f(x) = \sqrt{x - 2}$. The expression inside the square root must be non-negative for the function to be real-valued. Therefore, $x - 2 \geq 0$, which simplifies to $x \geq 2$.

Since $x \geq 2$, the function starts at $x = 2$. At $x = 2$, $f(2) = \sqrt{2 - 2} = \sqrt{0} = 0$. So, the point (2, 0) is on the graph.

The function $f(x) = \sqrt{x - 2}$ is a square root function shifted 2 units to the right. The graph will start at (2, 0) and increase slowly as $x$ increases.

Final Answer