Questions: How many moles of N2 reacted if 0.50 mol of NH3 is produced?

Transcript text: How many moles of $\mathrm{N}_{2}$ reacted if 0.50 mol of $\mathrm{NH}_{3}$ is produced?

Solution

Solution Steps

Step 1: Write the Balanced Chemical Equation

The production of ammonia ($\mathrm{NH}_3$) from nitrogen ($\mathrm{N}_2$) and hydrogen ($\mathrm{H}_2$) is described by the Haber process. The balanced chemical equation for this reaction is:

\[ \mathrm{N}_2 + 3\mathrm{H}_2 \rightarrow 2\mathrm{NH}_3 \]

Step 2: Determine the Mole Ratio

From the balanced equation, we can see that 1 mole of $\mathrm{N}_2$ produces 2 moles of $\mathrm{NH}_3$. Therefore, the mole ratio of $\mathrm{N}_2$ to $\mathrm{NH}_3$ is 1:2.

Step 3: Calculate the Moles of $\mathrm{N}_2$ Reacted

Given that 0.50 moles of $\mathrm{NH}_3$ are produced, we can use the mole ratio to find the moles of $\mathrm{N}_2$ that reacted:

\[ \text{Moles of } \mathrm{N}_2 = \frac{0.50 \, \text{moles of } \mathrm{NH}_3}{2} = 0.25 \, \text{moles of } \mathrm{N}_2 \]