Questions: Part C 0.20 M KI Express your answer to two decimal places.

Transcript text: Part C 0.20 M KI Express your answer to two decimal places. View Available Hint(s) $\square$ Submit Provide Feedback

Solution

Solution Steps

It seems like the question is incomplete, as it only provides a concentration of a solution (0.20 M KI) without specifying what needs to be calculated or expressed. However, I will assume that you want to express the concentration of the KI solution in a different unit or context.

For the sake of this exercise, let's assume the task is to express the concentration of the KI solution in terms of grams per liter (g/L).

Step 1: Determine the Molar Mass of KI

The molar mass of potassium iodide (KI) is calculated by adding the atomic masses of potassium (K) and iodine (I):

Potassium (K): 39.10 g/mol
Iodine (I): 126.90 g/mol

\[ \text{Molar mass of KI} = 39.10 \, \text{g/mol} + 126.90 \, \text{g/mol} = 166.00 \, \text{g/mol} \]

Step 2: Convert Molarity to Grams per Liter

Molarity (M) is defined as moles of solute per liter of solution. To convert this to grams per liter, multiply the molarity by the molar mass of the solute:

\[ 0.20 \, \text{M} \times 166.00 \, \text{g/mol} = 33.20 \, \text{g/L} \]