Questions: Question 4 Problem may be attempted multiple times 0.00 points out of 1.00 Part 1 Calculate the displacement and velocity at a time of 0.500 s. displacement: velocity: Part 2 Calculate the displacement and velocity at a time of 1.00 s. displacement: velocity:

Solution Steps

To solve this problem, we need to calculate the displacement and velocity at two different times: 0.500 s and 1.00 s. However, the problem does not provide specific information about the motion, such as initial velocity, acceleration, or the type of motion (e.g., uniform, uniformly accelerated). For the sake of this solution, let's assume the motion is uniformly accelerated, and we have the following general equations of motion:

1. Displacement: \[ s = ut + \frac{1}{2} a t^2 \] where \( s \) is the displacement, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.

2. Velocity: \[ v = u + at \] where \( v \) is the velocity at time \( t \).

Assuming initial velocity \( u = 0 \) and acceleration \( a = 0 \) (for simplicity, as no values are provided):

• Displacement at 0.500 s: \[ s = 0 \times 0.500 + \frac{1}{2} \times 0 \times (0.500)^2 = 0 \]

• Velocity at 0.500 s: \[ v = 0 + 0 \times 0.500 = 0 \]

Using the same assumptions:

• Displacement at 1.00 s: \[ s = 0 \times 1.00 + \frac{1}{2} \times 0 \times (1.00)^2 = 0 \]

• Velocity at 1.00 s: \[ v = 0 + 0 \times 1.00 = 0 \]

Final Answer