Questions: Trial Exp v1f (m / s) Acc V1f (m / s) % Error Exp v2f (m / s) Acc v2f (m / s) % Error ml=m 2 1.00 2.00 0 0 ml>m 2 2.00 2.00 0 0 m 1<m 2 1.00 1.00 N/A N/A

Transcript text: Trial & Exp v1f $(\mathrm{m} / \mathrm{s})$ & Acc V1f $(\mathrm{m} / \mathrm{s})$ & \% Error & Exp v2f $(\mathrm{m} / \mathrm{s})$ & Acc v2f $(\mathrm{m} / \mathbf{s})$ & \% Error \\ $\mathrm{ml}=\mathrm{m} 2$ & 1.00 & 2.00 & 0 & & & 0 \\ $\mathrm{ml}>\mathrm{m} 2$ & 2.00 & 2.00 & 0 & & & 0 \\ $\mathrm{~m} 1<\mathrm{m} 2$ & 1.00 & 1.00 & N/A & & & N/A \\

Solution

Solution Steps

Step 1: Understanding the Table

The table presents data from three trials, each with different conditions regarding the masses $ m_1 $ and $ m_2 $. The columns include experimental and accepted final velocities ($ v1f $ and $ v2f $) for two objects, along with the percentage error for each measurement.

Step 2: Analyzing the Data

Trial 1 ($ m_1 = m_2 $):
- Experimental $ v1f = 1.00 \, \text{m/s} $
- Accepted $ v1f = 2.00 \, \text{m/s} $
- Percentage error for $ v1f = 0\% $
- No data for $ v2f $.
Trial 2 ($ m_1 > m_2 $):
- Experimental $ v1f = 2.00 \, \text{m/s} $
- Accepted $ v1f = 2.00 \, \text{m/s} $
- Percentage error for $ v1f = 0\% $
- No data for $ v2f $.
Trial 3 ($ m_1 < m_2 $):
- Experimental $ v1f = 1.00 \, \text{m/s} $
- Accepted $ v1f = 1.00 \, \text{m/s} $
- Percentage error for $ v1f = \text{N/A} $
- No data for $ v2f $.

Step 3: Calculating Percentage Error

The percentage error is calculated using the formula: \[ \% \text{Error} = \left( \frac{\text{Experimental Value} - \text{Accepted Value}}{\text{Accepted Value}} \right) \times 100\% \]

Trial 1: \[ \% \text{Error} = \left( \frac{1.00 - 2.00}{2.00} \right) \times 100\% = -50\% \]
Trial 2: \[ \% \text{Error} = \left( \frac{2.00 - 2.00}{2.00} \right) \times 100\% = 0\% \]
Trial 3: \[ \% \text{Error} = \left( \frac{1.00 - 1.00}{1.00} \right) \times 100\% = 0\% \]