Questions: Given the following compound C8H10N4O2 Answer the following: Given the moles of Hydrogen (H) which of the following is the conversion factor to calculate the moles of C8H10N4O2 ? [Select] 1) 1 mol H / 10 mol C8H10N4O2 2) 10 mol H / 1 mol C8H10N4O2 4) 1 mol C8H10N4O2 / 10 mol H Given the moles of C8H10N4O2 which of the following is the conversion factor to calculate the moles of carbon (C)? [Select] 1) 1 mol C / 8 mol C8H10N4O2 2) 8 mol C / 1 mol C8H10N4O2 3) 8 mol C8H10N4O2 / 1 mol C 4) 1 mol C8H10N4O2 / 8 mol H

Given the following compound C8H10N4O2 Answer the following: Given the moles of Hydrogen (H) which of the following is the conversion factor to calculate the moles of C8H10N4O2 ? [Select] 1) 1 mol H / 10 mol C8H10N4O2 2) 10 mol H / 1 mol C8H10N4O2 4) 1 mol C8H10N4O2 / 10 mol H Given the moles of C8H10N4O2 which of the following is the conversion factor to calculate the moles of carbon (C)? [Select] 1) 1 mol C / 8 mol C8H10N4O2 2) 8 mol C / 1 mol C8H10N4O2 3) 8 mol C8H10N4O2 / 1 mol C 4) 1 mol C8H10N4O2 / 8 mol H
Transcript text: Given the following compound \[ \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2} \] Answer the following: Given the moles of Hydrogen $(\mathrm{H})$ which of the following is the conversion factor to calculate the moles of $\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}$ ? [Select] 1) $\frac{1 \mathrm{~mol} \mathrm{H}_{\mathrm{H}}}{10 \mathrm{~mol} \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}$ 2) $\frac{10 \mathrm{~mol} \mathrm{H}}{1 \mathrm{~mol} \mathrm{Cl}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}$ 4) $\frac{1 \mathrm{~mol}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}{10 \mathrm{~mol} \mathrm{H}}$ Given the moles of $\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}$ which of the following is the conversion factor to calculate the moles of carbon (C)? [Select] $\square$ 1) $\frac{1 \mathrm{~mol} \mathrm{C}}{8 \mathrm{~mol} \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}$ 2) $\frac{8 \mathrm{~mol} \mathrm{C}}{1 \mathrm{~mol} \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}$ 3) $\frac{8 \mathrm{~mol} \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}{1 \mathrm{~mol} \mathrm{C}}$ 4) $\frac{1 \mathrm{~mol} \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}{8 \mathrm{~mol} \mathrm{H}}$
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Solution

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Solution Steps

Step 1: Understanding the Compound Formula

The compound given is \(\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}\). This indicates that each molecule of the compound contains 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

Step 2: Conversion Factor for Moles of Hydrogen to Moles of Compound

To find the conversion factor from moles of hydrogen to moles of the compound, we need to consider the number of hydrogen atoms in one molecule of the compound. There are 10 hydrogen atoms per molecule of \(\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}\). Therefore, the conversion factor is: \[ \frac{1 \text{ mol } \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}{10 \text{ mol } \mathrm{H}} \]

Step 3: Conversion Factor for Moles of Compound to Moles of Carbon

To find the conversion factor from moles of the compound to moles of carbon, we consider the number of carbon atoms in one molecule of the compound. There are 8 carbon atoms per molecule of \(\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}\). Therefore, the conversion factor is: \[ \frac{8 \text{ mol } \mathrm{C}}{1 \text{ mol } \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}} \]

Final Answer

  1. Conversion factor for moles of hydrogen to moles of compound: \(\boxed{\frac{1 \text{ mol } \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}{10 \text{ mol } \mathrm{H}}}\)
  2. Conversion factor for moles of compound to moles of carbon: \(\boxed{\frac{8 \text{ mol } \mathrm{C}}{1 \text{ mol } \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{O}_{2}}}\)
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