Questions: [5 3 5; 1 5 0] * [-4 2; -3 4; 3 -5]

[5 3 5; 1 5 0] * [-4 2; -3 4; 3 -5]
Transcript text: $\left[\begin{array}{lll}5 & 3 & 5 \\ 1 & 5 & 0\end{array}\right] \cdot\left[\begin{array}{cc}-4 & 2 \\ -3 & 4 \\ 3 & -5\end{array}\right]$
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Solution

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Solution Steps

Step 1: Verify Matrix Dimensions

Matrix A Dimensions: 2x3 Matrix B Dimensions: 3x2 The number of columns in Matrix A is equal to the number of rows in Matrix B, so we can proceed.

Step 2: Initialize Matrix C

Matrix C will have dimensions 2x2.

Step 3: Compute Elements of Matrix C

c_{11} = (5_-4) + (3_-3) + (5_3) = -14 c_{12} = (5_2) + (3_4) + (5_-5) = -3 c_{21} = (1_-4) + (5_-3) + (0_3) = -19 c_{22} = (1_2) + (5_4) + (0_-5) = 22

Final Answer:

Matrix C (Result of AxB): [-14, -3] [-19, 22]

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